To create a solution of 100 mg per liter available chlorine, how much of 5.25 percent bleach should be mixed with one gallon of water?

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To determine how much of a 5.25% bleach solution is needed to create a solution with 100 mg per liter of available chlorine, it's important to understand the concentration of the bleach and how it gets diluted in water.

First, we need to calculate the amount of available chlorine in the bleach. A bleach solution that is 5.25% contains 5.25 grams of sodium hypochlorite per 100 milliliters of solution. This translates to 52.5 grams of sodium hypochlorite in one liter (1000 mL) of the bleach solution. Given that sodium hypochlorite is approximately 50% available chlorine by weight, this means that in one liter of 5.25% bleach, there are about 26.25 grams of available chlorine.

Next, we want to form a solution of 100 mg/L, which is equivalent to 0.1 g/L. Therefore, we need to find out how many liters of the 5.25% bleach solution would be required to get that concentration.

With 26.25 grams of available chlorine in one liter of bleach, to achieve a 0.1 g/L concentration, we can set up the following calculation:

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